3x-5=2(2x-3)0

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Solution for 3x-5=2(2x-3)0 equation: 



3x-5=2(2x-3)0

We move all terms to the left:

3x-5-(2(2x-3)0)=0



We calculate terms in parentheses: -(2(2x-3)0), so:

2(2x-3)0

We multiply parentheses

4x-6

Back to the equation:

-(4x-6)



We get rid of parentheses

3x-4x+6-5=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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