3x-5=2x+3-2(x-4)

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Solution for 3x-5=2x+3-2(x-4) equation: 



3x-5=2x+3-2(x-4)

We move all terms to the left:

3x-5-(2x+3-2(x-4))=0



We calculate terms in parentheses: -(2x+3-2(x-4)), so:

2x+3-2(x-4)

determiningTheFunctionDomain
2x-2(x-4)+3

We multiply parentheses

2x-2x+8+3

We add all the numbers together, and all the variables

11

Back to the equation:

-(11)



We add all the numbers together, and all the variables

3x-16=0

We move all terms containing x to the left, all other terms to the right

3x=16

x=16/3

x=5+1/3

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