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3x-5=x-2(1-2x)
We move all terms to the left:
3x-5-(x-2(1-2x))=0
We add all the numbers together, and all the variables
3x-(x-2(-2x+1))-5=0
We calculate terms in parentheses: -(x-2(-2x+1)), so:We get rid of parentheses
x-2(-2x+1)
We multiply parentheses
x+4x-2
We add all the numbers together, and all the variables
5x-2
Back to the equation:
-(5x-2)
3x-5x+2-5=0
We add all the numbers together, and all the variables
-2x-3=0
We move all terms containing x to the left, all other terms to the right
-2x=3
x=3/-2
x=-1+1/2
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