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3x-5x(x-2)=3
We move all terms to the left:
3x-5x(x-2)-(3)=0
We multiply parentheses
-5x^2+3x+10x-3=0
We add all the numbers together, and all the variables
-5x^2+13x-3=0
a = -5; b = 13; c = -3;
Δ = b2-4ac
Δ = 132-4·(-5)·(-3)
Δ = 109
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{109}}{2*-5}=\frac{-13-\sqrt{109}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{109}}{2*-5}=\frac{-13+\sqrt{109}}{-10} $
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