3x-6=3x(x-1)+12

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Solution for 3x-6=3x(x-1)+12 equation: 



3x-6=3x(x-1)+12

We move all terms to the left:

3x-6-(3x(x-1)+12)=0



We calculate terms in parentheses: -(3x(x-1)+12), so:

3x(x-1)+12

We multiply parentheses

3x^2-3x+12

Back to the equation:

-(3x^2-3x+12)



We get rid of parentheses

-3x^2+3x+3x-12-6=0

We add all the numbers together, and all the variables

-3x^2+6x-18=0

a = -3; b = 6; c = -18;
Δ = b2-4ac
Δ = 62-4·(-3)·(-18)
Δ = -180
Delta is less than zero, so there is no solution for the equation

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