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3x-6x^2=8x+20-5x
We move all terms to the left:
3x-6x^2-(8x+20-5x)=0
We add all the numbers together, and all the variables
-6x^2+3x-(3x+20)=0
We get rid of parentheses
-6x^2+3x-3x-20=0
We add all the numbers together, and all the variables
-6x^2-20=0
a = -6; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·(-6)·(-20)
Δ = -480
Delta is less than zero, so there is no solution for the equation
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