3x-7+(x-3)=16

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Solution for 3x-7+(x-3)=16 equation: 



3x-7+(x-3)=16

We move all terms to the left:

3x-7+(x-3)-(16)=0

We add all the numbers together, and all the variables

3x+(x-3)-23=0

We get rid of parentheses

3x+x-3-23=0

We add all the numbers together, and all the variables

4x-26=0

We move all terms containing x to the left, all other terms to the right

4x=26

x=26/4

x=6+1/2

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