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3x-7+4(x-3)=5x+3-2(x-3)
We move all terms to the left:
3x-7+4(x-3)-(5x+3-2(x-3))=0
We multiply parentheses
3x+4x-(5x+3-2(x-3))-12-7=0
We calculate terms in parentheses: -(5x+3-2(x-3)), so:We add all the numbers together, and all the variables
5x+3-2(x-3)
determiningTheFunctionDomain 5x-2(x-3)+3
We multiply parentheses
5x-2x+6+3
We add all the numbers together, and all the variables
3x+9
Back to the equation:
-(3x+9)
7x-(3x+9)-19=0
We get rid of parentheses
7x-3x-9-19=0
We add all the numbers together, and all the variables
4x-28=0
We move all terms containing x to the left, all other terms to the right
4x=28
x=28/4
x=7
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