3x-7-4(5+x)=x-50

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Solution for 3x-7-4(5+x)=x-50 equation: 



3x-7-4(5+x)=x-50

We move all terms to the left:

3x-7-4(5+x)-(x-50)=0

We add all the numbers together, and all the variables

3x-4(x+5)-(x-50)-7=0

We multiply parentheses

3x-4x-(x-50)-20-7=0

We get rid of parentheses

3x-4x-x+50-20-7=0

We add all the numbers together, and all the variables

-2x+23=0

We move all terms containing x to the left, all other terms to the right

-2x=-23

x=-23/-2

x=11+1/2

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