3x-7/x+5=x-3/x+2

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Solution for 3x-7/x+5=x-3/x+2 equation:



3x-7/x+5=x-3/x+2
We move all terms to the left:
3x-7/x+5-(x-3/x+2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x+2)!=0
x∈R
We get rid of parentheses
3x-7/x-x+3/x-2+5=0
We multiply all the terms by the denominator
3x*x-x*x-2*x+5*x-7+3=0
We add all the numbers together, and all the variables
3x+3x*x-x*x-4=0
Wy multiply elements
3x^2-1x^2+3x-4=0
We add all the numbers together, and all the variables
2x^2+3x-4=0
a = 2; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·2·(-4)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{41}}{2*2}=\frac{-3-\sqrt{41}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{41}}{2*2}=\frac{-3+\sqrt{41}}{4} $

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