3x-7=3(2x-5)-3+2(x-2)

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Solution for 3x-7=3(2x-5)-3+2(x-2) equation: 



3x-7=3(2x-5)-3+2(x-2)

We move all terms to the left:

3x-7-(3(2x-5)-3+2(x-2))=0



We calculate terms in parentheses: -(3(2x-5)-3+2(x-2)), so:

3(2x-5)-3+2(x-2)

determiningTheFunctionDomain
3(2x-5)+2(x-2)-3

We multiply parentheses

6x+2x-15-4-3

We add all the numbers together, and all the variables

8x-22

Back to the equation:

-(8x-22)



We get rid of parentheses

3x-8x+22-7=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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