3x-7y=35;12x-28y=140

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2x+y=8
x+3y=14

Solution for 3x-7y=35;12x-28y=140 system of equations: 


  • /| 3*x-(7*y)-35 = 0| 12*x-(28*y)-140 = 0
  • We try to solve the equation: 3*x-(7*y)-35 = 0
  • 3*x-7*y-35 = 0 // - 3*x-35
  • -7*y = -(3*x-35) // : -7
  • y = (-(3*x-35))/(-7)
  • y = (35-(3*x))/(-7)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 12*x-(28*((35-(3*x))/(-7)))-140 = 0| y = (35-(3*x))/(-7)
  • (-1*28*(35-3*x))/(-7)+12*x-140 = 0
  • 140-140 = 0
  • 0 = 0
  • The system of equations has infinitely many solutions

 

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