3x-8(x+2)=5(4-3x)-1

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Solution for 3x-8(x+2)=5(4-3x)-1 equation: 



3x-8(x+2)=5(4-3x)-1

We move all terms to the left:

3x-8(x+2)-(5(4-3x)-1)=0

We add all the numbers together, and all the variables

3x-8(x+2)-(5(-3x+4)-1)=0

We multiply parentheses

3x-8x-(5(-3x+4)-1)-16=0



We calculate terms in parentheses: -(5(-3x+4)-1), so:

5(-3x+4)-1

We multiply parentheses

-15x+20-1

We add all the numbers together, and all the variables

-15x+19

Back to the equation:

-(-15x+19)



We add all the numbers together, and all the variables

-5x-(-15x+19)-16=0

We get rid of parentheses

-5x+15x-19-16=0

We add all the numbers together, and all the variables

10x-35=0

We move all terms containing x to the left, all other terms to the right

10x=35

x=35/10

x=3+1/2

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