3x-8(x-5)=7+4x+20

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Solution for 3x-8(x-5)=7+4x+20 equation: 



3x-8(x-5)=7+4x+20

We move all terms to the left:

3x-8(x-5)-(7+4x+20)=0

We add all the numbers together, and all the variables

3x-8(x-5)-(4x+27)=0

We multiply parentheses

3x-8x-(4x+27)+40=0

We get rid of parentheses

3x-8x-4x-27+40=0

We add all the numbers together, and all the variables

-9x+13=0

We move all terms containing x to the left, all other terms to the right

-9x=-13

x=-13/-9

x=1+4/9

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