3x-8+11x=8(3x-2)+16

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Solution for 3x-8+11x=8(3x-2)+16 equation: 



3x-8+11x=8(3x-2)+16

We move all terms to the left:

3x-8+11x-(8(3x-2)+16)=0

We add all the numbers together, and all the variables

14x-(8(3x-2)+16)-8=0



We calculate terms in parentheses: -(8(3x-2)+16), so:

8(3x-2)+16

We multiply parentheses

24x-16+16

We add all the numbers together, and all the variables

24x

Back to the equation:

-(24x)



We add all the numbers together, and all the variables

-10x-8=0

We move all terms containing x to the left, all other terms to the right

-10x=8

x=8/-10

x=-4/5

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