3x-8+2x-4=2(2x-4)+x-4

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Solution for 3x-8+2x-4=2(2x-4)+x-4 equation: 



3x-8+2x-4=2(2x-4)+x-4

We move all terms to the left:

3x-8+2x-4-(2(2x-4)+x-4)=0

We add all the numbers together, and all the variables

5x-(2(2x-4)+x-4)-12=0



We calculate terms in parentheses: -(2(2x-4)+x-4), so:

2(2x-4)+x-4

We add all the numbers together, and all the variables

x+2(2x-4)-4

We multiply parentheses

x+4x-8-4

We add all the numbers together, and all the variables

5x-12

Back to the equation:

-(5x-12)



We get rid of parentheses

5x-5x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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