3x-8+2x-4=2(2x-4+x-4)

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Solution for 3x-8+2x-4=2(2x-4+x-4) equation: 



3x-8+2x-4=2(2x-4+x-4)

We move all terms to the left:

3x-8+2x-4-(2(2x-4+x-4))=0

We add all the numbers together, and all the variables

3x+2x-(2(3x-8))-8-4=0

We add all the numbers together, and all the variables

5x-(2(3x-8))-12=0



We calculate terms in parentheses: -(2(3x-8)), so:

2(3x-8)

We multiply parentheses

6x-16

Back to the equation:

-(6x-16)



We get rid of parentheses

5x-6x+16-12=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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