3x-8+2x=3(3x-3)=2

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Solution for 3x-8+2x=3(3x-3)=2 equation: 



3x-8+2x=3(3x-3)=2

We move all terms to the left:

3x-8+2x-(3(3x-3))=0

We add all the numbers together, and all the variables

5x-(3(3x-3))-8=0



We calculate terms in parentheses: -(3(3x-3)), so:

3(3x-3)

We multiply parentheses

9x-9

Back to the equation:

-(9x-9)



We get rid of parentheses

5x-9x+9-8=0

We add all the numbers together, and all the variables

-4x+1=0

We move all terms containing x to the left, all other terms to the right

-4x=-1

x=-1/-4

x=1/4

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