3x-8=(x-4)+1

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Solution for 3x-8=(x-4)+1 equation: 



3x-8=(x-4)+1

We move all terms to the left:

3x-8-((x-4)+1)=0



We calculate terms in parentheses: -((x-4)+1), so:

(x-4)+1

We get rid of parentheses

x-4+1

We add all the numbers together, and all the variables

x-3

Back to the equation:

-(x-3)



We get rid of parentheses

3x-x+3-8=0

We add all the numbers together, and all the variables

2x-5=0

We move all terms containing x to the left, all other terms to the right

2x=5

x=5/2

x=2+1/2

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