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3x-8=-x(x-2)
We move all terms to the left:
3x-8-(-x(x-2))=0
We calculate terms in parentheses: -(-x(x-2)), so:We get rid of parentheses
-x(x-2)
We multiply parentheses
-x^2+2x
We add all the numbers together, and all the variables
-1x^2+2x
Back to the equation:
-(-1x^2+2x)
1x^2-2x+3x-8=0
We add all the numbers together, and all the variables
x^2+x-8=0
a = 1; b = 1; c = -8;
Δ = b2-4ac
Δ = 12-4·1·(-8)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{33}}{2*1}=\frac{-1-\sqrt{33}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{33}}{2*1}=\frac{-1+\sqrt{33}}{2} $
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