3x-8=16(1-2x)+16

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Solution for 3x-8=16(1-2x)+16 equation: 



3x-8=16(1-2x)+16

We move all terms to the left:

3x-8-(16(1-2x)+16)=0

We add all the numbers together, and all the variables

3x-(16(-2x+1)+16)-8=0



We calculate terms in parentheses: -(16(-2x+1)+16), so:

16(-2x+1)+16

We multiply parentheses

-32x+16+16

We add all the numbers together, and all the variables

-32x+32

Back to the equation:

-(-32x+32)



We get rid of parentheses

3x+32x-32-8=0

We add all the numbers together, and all the variables

35x-40=0

We move all terms containing x to the left, all other terms to the right

35x=40

x=40/35

x=1+1/7

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