3x-8=3(x-4)+-

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Solution for 3x-8=3(x-4)+- equation: 



3x-8=3(x-4)+-

We move all terms to the left:

3x-8-(3(x-4)+-)=0

We use the square of the difference formula

3x-(3(x-4)-)-8=0



We calculate terms in parentheses: -(3(x-4)-), so:

3(x-4)-

We add all the numbers together, and all the variables

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

3x-3x+12-8=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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