3x-8=4(2-3x)-8x

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Solution for 3x-8=4(2-3x)-8x equation: 



3x-8=4(2-3x)-8x

We move all terms to the left:

3x-8-(4(2-3x)-8x)=0

We add all the numbers together, and all the variables

3x-(4(-3x+2)-8x)-8=0



We calculate terms in parentheses: -(4(-3x+2)-8x), so:

4(-3x+2)-8x

We add all the numbers together, and all the variables

-8x+4(-3x+2)

We multiply parentheses

-8x-12x+8

We add all the numbers together, and all the variables

-20x+8

Back to the equation:

-(-20x+8)



We get rid of parentheses

3x+20x-8-8=0

We add all the numbers together, and all the variables

23x-16=0

We move all terms containing x to the left, all other terms to the right

23x=16

x=16/23

x=16/23

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