3x-8=4(6+3x)+2x+1

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Solution for 3x-8=4(6+3x)+2x+1 equation: 



3x-8=4(6+3x)+2x+1

We move all terms to the left:

3x-8-(4(6+3x)+2x+1)=0

We add all the numbers together, and all the variables

3x-(4(3x+6)+2x+1)-8=0



We calculate terms in parentheses: -(4(3x+6)+2x+1), so:

4(3x+6)+2x+1

We add all the numbers together, and all the variables

2x+4(3x+6)+1

We multiply parentheses

2x+12x+24+1

We add all the numbers together, and all the variables

14x+25

Back to the equation:

-(14x+25)



We get rid of parentheses

3x-14x-25-8=0

We add all the numbers together, and all the variables

-11x-33=0

We move all terms containing x to the left, all other terms to the right

-11x=33

x=33/-11

x=-3

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