3x-8=6(2-2x)+16

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Solution for 3x-8=6(2-2x)+16 equation: 



3x-8=6(2-2x)+16

We move all terms to the left:

3x-8-(6(2-2x)+16)=0

We add all the numbers together, and all the variables

3x-(6(-2x+2)+16)-8=0



We calculate terms in parentheses: -(6(-2x+2)+16), so:

6(-2x+2)+16

We multiply parentheses

-12x+12+16

We add all the numbers together, and all the variables

-12x+28

Back to the equation:

-(-12x+28)



We get rid of parentheses

3x+12x-28-8=0

We add all the numbers together, and all the variables

15x-36=0

We move all terms containing x to the left, all other terms to the right

15x=36

x=36/15

x=2+2/5

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