3x-9=4(x-3)+18

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Solution for 3x-9=4(x-3)+18 equation: 



3x-9=4(x-3)+18

We move all terms to the left:

3x-9-(4(x-3)+18)=0



We calculate terms in parentheses: -(4(x-3)+18), so:

4(x-3)+18

We multiply parentheses

4x-12+18

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We get rid of parentheses

3x-4x-6-9=0

We add all the numbers together, and all the variables

-1x-15=0

We move all terms containing x to the left, all other terms to the right

-x=15

x=15/-1

x=-15

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