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3x-9=9/x+5
We move all terms to the left:
3x-9-(9/x+5)=0
Domain of the equation: x+5)!=0We get rid of parentheses
x∈R
3x-9/x-5-9=0
We multiply all the terms by the denominator
3x*x-5*x-9*x-9=0
We add all the numbers together, and all the variables
-14x+3x*x-9=0
Wy multiply elements
3x^2-14x-9=0
a = 3; b = -14; c = -9;
Δ = b2-4ac
Δ = -142-4·3·(-9)
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-4\sqrt{19}}{2*3}=\frac{14-4\sqrt{19}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+4\sqrt{19}}{2*3}=\frac{14+4\sqrt{19}}{6} $
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