3x-9x(x-1)=6x-3x(3x-2)

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Solution for 3x-9x(x-1)=6x-3x(3x-2) equation: 



3x-9x(x-1)=6x-3x(3x-2)

We move all terms to the left:

3x-9x(x-1)-(6x-3x(3x-2))=0

We multiply parentheses

-9x^2+3x+9x-(6x-3x(3x-2))=0



We calculate terms in parentheses: -(6x-3x(3x-2)), so:

6x-3x(3x-2)

We multiply parentheses

-9x^2+6x+6x

We add all the numbers together, and all the variables

-9x^2+12x

Back to the equation:

-(-9x^2+12x)



We add all the numbers together, and all the variables

-9x^2-(-9x^2+12x)+12x=0

We get rid of parentheses

-9x^2+9x^2-12x+12x=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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