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3x-x+2=2(x+1)
We move all terms to the left:
3x-x+2-(2(x+1))=0
We add all the numbers together, and all the variables
2x-(2(x+1))+2=0
We calculate terms in parentheses: -(2(x+1)), so:We get rid of parentheses
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
-(2x+2)
2x-2x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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