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3x-x-5=2(x+2)
We move all terms to the left:
3x-x-5-(2(x+2))=0
We add all the numbers together, and all the variables
2x-(2(x+2))-5=0
We calculate terms in parentheses: -(2(x+2)), so:We get rid of parentheses
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
2x-2x-4-5=0
We add all the numbers together, and all the variables
-9!=0
There is no solution for this equation
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