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3x-x-5=2(x+2)-3
We move all terms to the left:
3x-x-5-(2(x+2)-3)=0
We add all the numbers together, and all the variables
2x-(2(x+2)-3)-5=0
We calculate terms in parentheses: -(2(x+2)-3), so:We get rid of parentheses
2(x+2)-3
We multiply parentheses
2x+4-3
We add all the numbers together, and all the variables
2x+1
Back to the equation:
-(2x+1)
2x-2x-1-5=0
We add all the numbers together, and all the variables
-6!=0
There is no solution for this equation
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