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3x-x-5=3(x+3)-9
We move all terms to the left:
3x-x-5-(3(x+3)-9)=0
We add all the numbers together, and all the variables
2x-(3(x+3)-9)-5=0
We calculate terms in parentheses: -(3(x+3)-9), so:We add all the numbers together, and all the variables
3(x+3)-9
We multiply parentheses
3x+9-9
We add all the numbers together, and all the variables
3x
Back to the equation:
-(3x)
-1x-5=0
We move all terms containing x to the left, all other terms to the right
-x=5
x=5/-1
x=-5
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