3x/(x-2)-8/(x-4)=3

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Solution for 3x/(x-2)-8/(x-4)=3 equation: 


D( x )

x-2 = 0

x-4 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:2) U (2:4) U (4:+oo)

(3*x)/(x-2)-(8/(x-4)) = 3 // - 3

(3*x)/(x-2)-(8/(x-4))-3 = 0

(3*x)/(x-2)-8*(x-4)^-1-3 = 0

(3*x)/(x-2)-8/(x-4)-3 = 0

(3*x*(x-4))/((x-2)*(x-4))+(-8*(x-2))/((x-2)*(x-4))+(-3*(x-2)*(x-4))/((x-2)*(x-4)) = 0

3*x*(x-4)-8*(x-2)-3*(x-2)*(x-4) = 0

3*x^2-3*x^2-20*x+18*x-24+16 = 0

-2*x-8 = 0

(-2*x-8)/((x-2)*(x-4)) = 0

(-2*x-8)/((x-2)*(x-4)) = 0 // * (x-2)*(x-4)

-2*x-8 = 0

-2*x-8 = 0 // + 8

-2*x = 8 // : -2

x = 8/(-2)

x = -4

x = -4

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