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3x/12=5x/x+12
We move all terms to the left:
3x/12-(5x/x+12)=0
Domain of the equation: x+12)!=0We get rid of parentheses
x∈R
3x/12-5x/x-12=0
We calculate fractions
3x^2/12x+(-60x)/12x-12=0
We multiply all the terms by the denominator
3x^2+(-60x)-12*12x=0
Wy multiply elements
3x^2+(-60x)-144x=0
We get rid of parentheses
3x^2-60x-144x=0
We add all the numbers together, and all the variables
3x^2-204x=0
a = 3; b = -204; c = 0;
Δ = b2-4ac
Δ = -2042-4·3·0
Δ = 41616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{41616}=204$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-204)-204}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-204)+204}{2*3}=\frac{408}{6} =68 $
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