3x/4-2(x-3)=x-(x/3-7)+11/12

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Solution for 3x/4-2(x-3)=x-(x/3-7)+11/12 equation:


x in (-oo:+oo)

(3*x)/4-(2*(x-3)) = x-(x/3)+11/12+7 // - x-(x/3)+11/12+7

(3*x)/4-(2*(x-3))-x+x/3-(11/12)-7 = 0

(3*x)/4-2*(x-3)-x+x/3-11/12-7 = 0

(-2*3*4*12*(x-3))/(3*4*12)+(3*3*12*x)/(3*4*12)+(3*4*12*(-x))/(3*4*12)+(4*12*x)/(3*4*12)+(-11*3*4)/(3*4*12)+(-7*3*4*12)/(3*4*12) = 0

3*3*12*x-2*3*4*12*(x-3)+3*4*12*(-x)+4*12*x-11*3*4-7*3*4*12 = 0

48*x-180*x-144*x-1008-132+864 = 0

48*x-324*x-1008-132+864 = 0

864-276*x-1008-132 = 0

732-276*x-1008 = 0

-276*x-276 = 0

(-276*x-276)/(3*4*12) = 0

(-276*x-276)/(3*4*12) = 0 // * 3*4*12

-276*x-276 = 0

-276*x-276 = 0 // + 276

-276*x = 276 // : -276

x = 276/(-276)

x = -1

x = -1

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