3x/4-21x/32=-1*(1/8)

Solution for 3x/4-21x/32=-1*(1/8) equation:

3x/4-21x/32=-1(1/8)

We move all terms to the left:

3x/4-21x/32-(-1(1/8))=0

We add all the numbers together, and all the variables

3x/4-21x/32-(-1(+1/8))=0

We calculate fractions


(-5376x^2)/()+6144x^2/()+()/()=0

We add all the numbers together, and all the variables

(-5376x^2)/()+6144x^2/()+1=0

We multiply all the terms by the denominator


(-5376x^2)+6144x^2+1*()=0

We add all the numbers together, and all the variables

6144x^2+(-5376x^2)=0

We get rid of parentheses

6144x^2-5376x^2=0

We add all the numbers together, and all the variables

768x^2=0

a = 768; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·768·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{1536}=0$