3x/4=(10+6x)/5

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Solution for 3x/4=(10+6x)/5 equation: 



3x/4=(10+6x)/5

We move all terms to the left:

3x/4-((10+6x)/5)=0

We add all the numbers together, and all the variables

3x/4-((6x+10)/5)=0

We calculate fractions


15x^2/()+(-((6x+10)*4)/()=0



We calculate terms in parentheses: +(-((6x+10)*4)/(), so:

-((6x+10)*4)/(

We multiply all the terms by the denominator


-((6x+10)*4)



We calculate terms in parentheses: -((6x+10)*4), so:

(6x+10)*4

We multiply parentheses

24x+40

Back to the equation:

-(24x+40)



We get rid of parentheses

-24x-40

Back to the equation:

+(-24x-40)



We get rid of parentheses

15x^2/()-24x-40=0

We multiply all the terms by the denominator


15x^2-24x*()-40*()=0

We add all the numbers together, and all the variables

15x^2-24x*()=0

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