3x/4x+3x/8x=5

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Solution for 3x/4x+3x/8x=5 equation: 



3x/4x+3x/8x=5

We move all terms to the left:

3x/4x+3x/8x-(5)=0



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R





Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



We calculate fractions


24x^2/32x^2+12x^2/32x^2-5=0

We multiply all the terms by the denominator


24x^2+12x^2-5*32x^2=0

We add all the numbers together, and all the variables

36x^2-5*32x^2=0

Wy multiply elements

36x^2-160x^2=0

We add all the numbers together, and all the variables

-124x^2=0

a = -124; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-124)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-248}=0$

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