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3x/4x=2x
We move all terms to the left:
3x/4x-(2x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-2x+3x/4x=0
We multiply all the terms by the denominator
-2x*4x+3x=0
We add all the numbers together, and all the variables
3x-2x*4x=0
Wy multiply elements
-8x^2+3x=0
a = -8; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-8)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-8}=\frac{-6}{-16} =3/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-8}=\frac{0}{-16} =0 $
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