3x/4x=3x+7/5x-8

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Solution for 3x/4x=3x+7/5x-8 equation: 


x in (-oo:+oo)

((3*x)/4)*x = 3*x+(7/5)*x-8 // - 3*x+(7/5)*x-8

((3*x)/4)*x-(3*x)-((7/5)*x)+8 = 0

((3*x)/4)*x-3*x+(-7/5)*x+8 = 0

3/4*x^2-22/5*x+8 = 0

DELTA = (-22/5)^2-(3/4*4*8)

DELTA = -116/25

DELTA < 0

x belongs to the empty set

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