3x/5-(x-3)/2=(x+2)/3

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Solution for 3x/5-(x-3)/2=(x+2)/3 equation:


x in (-oo:+oo)

(3*x)/5-((x-3)/2) = (x+2)/3 // - (x+2)/3

(3*x)/5-((x-3)/2)-((x+2)/3) = 0

(-1*(x-3))/2+(-1*(x+2))/3+(3*x)/5 = 0

(-1*3*5*(x-3))/(2*3*5)+(-1*2*5*(x+2))/(2*3*5)+(2*3*3*x)/(2*3*5) = 0

2*3*3*x-1*3*5*(x-3)-1*2*5*(x+2) = 0

18*x-25*x+25 = 0

25-7*x = 0

(25-7*x)/(2*3*5) = 0

(25-7*x)/(2*3*5) = 0 // * 2*3*5

25-7*x = 0

25-7*x = 0 // - 25

-7*x = -25 // : -7

x = -25/(-7)

x = 25/7

x = 25/7

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