3x/5=(2x+6)/3

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Solution for 3x/5=(2x+6)/3 equation: 



3x/5=(2x+6)/3

We move all terms to the left:

3x/5-((2x+6)/3)=0

We calculate fractions


9x^2/()+(-((2x+6)*5)/()=0



We calculate terms in parentheses: +(-((2x+6)*5)/(), so:

-((2x+6)*5)/(

We multiply all the terms by the denominator


-((2x+6)*5)



We calculate terms in parentheses: -((2x+6)*5), so:

(2x+6)*5

We multiply parentheses

10x+30

Back to the equation:

-(10x+30)



We get rid of parentheses

-10x-30

Back to the equation:

+(-10x-30)



We get rid of parentheses

9x^2/()-10x-30=0

We multiply all the terms by the denominator


9x^2-10x*()-30*()=0

We add all the numbers together, and all the variables

9x^2-10x*()=0

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