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3x/6x+1/x=1
We move all terms to the left:
3x/6x+1/x-(1)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: x!=0We calculate fractions
x∈R
3x^2/6x^2+6x/6x^2-1=0
We multiply all the terms by the denominator
3x^2+6x-1*6x^2=0
Wy multiply elements
3x^2-6x^2+6x=0
We add all the numbers together, and all the variables
-3x^2+6x=0
a = -3; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-3)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-3}=\frac{-12}{-6} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-3}=\frac{0}{-6} =0 $
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