3x/7+12=18

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Solution for 3x/7+12=18 equation: 



3x/7+12=18

We move all terms to the left:

3x/7+12-(18)=0

We add all the numbers together, and all the variables

3x/7-6=0

We multiply all the terms by the denominator


3x-6*7=0

We add all the numbers together, and all the variables

3x-42=0

We move all terms containing x to the left, all other terms to the right

3x=42

x=42/3

x=14

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