3x/7-4z=12

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Solution for 3x/7-4z=12 equation: 


x in (-oo:+oo)

(3*x)/7-(4*z) = 12 // - 12

(3*x)/7-(4*z)-12 = 0

(3*x)/7-4*z-12 = 0

3/7*x-4*z-12 = 0 // + -4*z-12

3/7*x = -(-4*z-12) // : 3/7

x = (-(-4*z-12))/3/7

x = 7/3*(12-(-4*z))

x = 7/3*(12-(-4*z))

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