3x/7=4-(x-2)/4

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Solution for 3x/7=4-(x-2)/4 equation: 



3x/7=4-(x-2)/4

We move all terms to the left:

3x/7-(4-(x-2)/4)=0

We calculate fractions


12x^2/()+(-(4-(x-2)*7)/()=0



We calculate terms in parentheses: +(-(4-(x-2)*7)/(), so:

-(4-(x-2)*7)/(

We multiply all the terms by the denominator


-(4-(x-2)*7)



We calculate terms in parentheses: -(4-(x-2)*7), so:

4-(x-2)*7

determiningTheFunctionDomain
-(x-2)*7+4

We multiply parentheses

-7x+14+4

We add all the numbers together, and all the variables

-7x+18

Back to the equation:

-(-7x+18)



We get rid of parentheses

7x-18

Back to the equation:

+(7x-18)



We get rid of parentheses

12x^2/()+7x-18=0

We multiply all the terms by the denominator


12x^2+7x*()-18*()=0

We add all the numbers together, and all the variables

12x^2+7x*()=0

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