3x/7=5(1-x)/3

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Solution for 3x/7=5(1-x)/3 equation: 



3x/7=5(1-x)/3

We move all terms to the left:

3x/7-(5(1-x)/3)=0

We add all the numbers together, and all the variables

3x/7-(5(-1x+1)/3)=0

We calculate fractions


9x^2/()+(-(5(-1x+1)*7)/()=0



We calculate terms in parentheses: +(-(5(-1x+1)*7)/(), so:

-(5(-1x+1)*7)/(

We multiply all the terms by the denominator


-(5(-1x+1)*7)



We calculate terms in parentheses: -(5(-1x+1)*7), so:

5(-1x+1)*7

We multiply parentheses

-35x+35

Back to the equation:

-(-35x+35)



We get rid of parentheses

35x-35

Back to the equation:

+(35x-35)



We get rid of parentheses

9x^2/()+35x-35=0

We multiply all the terms by the denominator


9x^2+35x*()-35*()=0

We add all the numbers together, and all the variables

9x^2+35x*()=0

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