3x2(4x-6)=18+x

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Solution for 3x2(4x-6)=18+x equation:



3x^2(4x-6)=18+x
We move all terms to the left:
3x^2(4x-6)-(18+x)=0
We add all the numbers together, and all the variables
3x^2(4x-6)-(x+18)=0
We get rid of parentheses
3x^2(4x-6)-x-18=0
We add all the numbers together, and all the variables
3x^2(4x-6)-1x-18=0
We move all terms containing x to the left, all other terms to the right
3x^2(4x-6)-1x=18

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