3x2(4x-6)=18+x

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Solution for 3x2(4x-6)=18+x equation: 



3x^2(4x-6)=18+x

We move all terms to the left:

3x^2(4x-6)-(18+x)=0

We add all the numbers together, and all the variables

3x^2(4x-6)-(x+18)=0

We get rid of parentheses

3x^2(4x-6)-x-18=0

We add all the numbers together, and all the variables

3x^2(4x-6)-1x-18=0

We move all terms containing x to the left, all other terms to the right

3x^2(4x-6)-1x=18

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