3x2+0.95x-0.01=0

Solution for 3x2+0.95x-0.01=0 equation:

3x^2+0.95x-0.01=0

a = 3; b = 0.95; c = -0.01;
Δ = b2-4ac
Δ = 0.952-4·3·(-0.01)
Δ = 1.0225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.95)-\sqrt{1.0225}}{2*3}=\frac{-0.95-\sqrt{1.0225}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.95)+\sqrt{1.0225}}{2*3}=\frac{-0.95+\sqrt{1.0225}}{6}
$