3x2+10x-272=0

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Solution for 3x2+10x-272=0 equation:



3x^2+10x-272=0
a = 3; b = 10; c = -272;
Δ = b2-4ac
Δ = 102-4·3·(-272)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-58}{2*3}=\frac{-68}{6} =-11+1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+58}{2*3}=\frac{48}{6} =8 $

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